A) \[(-1,1)\]
B) \[\pi \]
C) \[\pi /2\]
D) 1
Correct Answer: B
Solution :
Limit \[=\underset{x\to 0}{\mathop{\text{lim}}}\,\,\left( \frac{\cos (\pi {{\cos }^{2}}x).\pi .2\cos x(-\sin x)}{2x} \right)\] \[=\underset{x\to 0}{\mathop{\text{lim}}}\,\pi \cos (\pi {{\cos }^{2}}x).\cos x.\left( \frac{-\sin x}{x} \right)\] \[=\pi (-1).1.(-1)=\pi \].
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