A) 2
B) 4
C) ?2
D) ?4
Correct Answer: B
Solution :
Applying L-Hospital?s rule, \[\underset{x\to 9}{\mathop{\lim }}\,\frac{\frac{1}{2\sqrt{f(x)}}\cdot {f}'(x)}{\frac{1}{2\sqrt{x}}}=\frac{\frac{{f}'(9)}{\sqrt{f(9)}}}{\frac{1}{\sqrt{9}}}=\frac{\frac{4}{3}}{\frac{1}{3}}=4\]
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