A) (1, 1)
B) (?1, 1)
C) (1, ?1)
D) (0, 1)
Correct Answer: C
Solution :
\[\underset{x\to \infty }{\mathop{\lim }}\,\left( \frac{{{x}^{2}}+1}{x+1}-2x-\beta \right)=0\] Þ \[\underset{x\to \infty }{\mathop{\lim }}\,\frac{{{x}^{2}}(1-\alpha )-x(\alpha +\beta )+1-b}{x+1}=0\] Since the limit of the given expression is zero, therefore degree of the polynomial in numerator must be less than denominator. \ \[1-\alpha =0\] and \[\alpha +\beta =0\] Þ \[\alpha =1\] and \[\beta =-1\].You need to login to perform this action.
You will be redirected in
3 sec