A) 1
B) ? 1
C) ½
D) ?1/2
Correct Answer: D
Solution :
\[\underset{x\to 0}{\mathop{\text{lim}}}\,\frac{\cos (\sin x)-1}{{{x}^{2}}}\]=\[\underset{x\to 0}{\mathop{\text{lim}}}\,\frac{-2{{\sin }^{2}}\left( \frac{\sin x}{2} \right)}{{{x}^{2}}}=-2.\frac{1}{4}=\frac{-1}{2}\].
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