A) 0
B) 1
C) \[-1\]
D) None of these
Correct Answer: B
Solution :
\[\underset{x\to 0}{\mathop{\lim }}\,\frac{\int_{0}^{x}{\cos {{t}^{2}}dt}}{x}\] Applying L- Hospital rule, we get \[\underset{x\to 0}{\mathop{\lim }}\,\frac{\int_{0}^{x}{\cos {{t}^{2}}dt}}{x}=\underset{x\to 0}{\mathop{\lim }}\,\frac{\cos {{x}^{2}}}{1}=1\].You need to login to perform this action.
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