A) 12
B) 18
C) 24
D) 36
Correct Answer: B
Solution :
\[\underset{x\to 2}{\mathop{\lim }}\,\frac{\int\limits_{6}^{f(x)}{4{{t}^{3}}dt}}{x-2}\,\,(0/0\,\text{form})=\underset{x\to 2}{\mathop{\lim }}\,\frac{4{{(f(x))}^{3}}\times f'(x)}{1}\] \[=4{{(f(2))}^{3}}\times f'(2)=18\].You need to login to perform this action.
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