A) \[\frac{1}{3}\]
B) \[-\frac{2}{3}\]
C) \[\frac{2}{3}\]
D) 1
Correct Answer: B
Solution :
\[\underset{n\to \infty }{\mathop{\lim }}\,\frac{1-2+3-4+5-6+.....-2n}{\sqrt{{{n}^{2}}+1}+\sqrt{4{{n}^{2}}-1}}\] \[f(x)=y\]\[=\frac{-2}{1+2}=\frac{-2}{3}\].
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