JEE Main & Advanced Mathematics Functions Question Bank Limits

  • question_answer
    \[\underset{x\to \infty }{\mathop{\lim }}\,\frac{{{(x+1)}^{10}}+{{(x+2)}^{10}}+.....+{{(x+100)}^{10}}}{{{x}^{10}}+{{10}^{10}}}\] is equal to

    A)                 0

    B)                 1

    C)                 10

    D)                 100

    Correct Answer: D

    Solution :

                       \[\underset{x\to \infty }{\mathop{\lim }}\,\frac{{{(x+1)}^{10}}+{{(x+2)}^{10}}+......+{{(x+100)}^{10}}}{{{x}^{10}}+{{10}^{10}}}\]                                 \[=\underset{x\to \infty }{\mathop{\lim }}\,\frac{{{x}^{10}}\left[ {{\left( 1+\frac{1}{x} \right)}^{10}}+{{\left( 1+\frac{2}{x} \right)}^{10}}+...+{{\left( 1+\frac{100}{x} \right)}^{10}} \right]}{{{x}^{10}}\left[ 1+\frac{{{10}^{10}}}{{{x}^{10}}} \right]}=100\].


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