JEE Main & Advanced Mathematics Functions Question Bank Limits

  • question_answer
    The value of \[\underset{x\to 0}{\mathop{\lim }}\,\frac{\int_{0}^{x}{\cos {{t}^{2}}}}{x}\,dt\] is

    A)                 0

    B)                 1

    C)                 \[-1\]

    D)                 None of these

    Correct Answer: B

    Solution :

                       \[\underset{x\to 0}{\mathop{\lim }}\,\frac{\int_{0}^{x}{\cos {{t}^{2}}dt}}{x}\] Applying L- Hospital rule, we get \[\underset{x\to 0}{\mathop{\lim }}\,\frac{\int_{0}^{x}{\cos {{t}^{2}}dt}}{x}=\underset{x\to 0}{\mathop{\lim }}\,\frac{\cos {{x}^{2}}}{1}=1\].


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