JEE Main & Advanced Mathematics Functions Question Bank Limits

  • question_answer
    \[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin {{x}^{o}}}{x}=\]

    A)                 1

    B)                 \[\pi /180\]

    C)                 Does not exist

    D)                 None of these

    Correct Answer: B

    Solution :

                    \[\underset{x\to 0}{\mathop{\lim }}\,\,\frac{\sin {{x}^{o}}}{x}=\underset{x\to 0}{\mathop{\lim }}\,\,\frac{\sin \frac{\pi x}{180}}{x}=\frac{\pi }{180}\] \[\left\{ \because \,x{}^\circ =\frac{\pi x}{180}\,radian \right\}\].


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