A) \[\underset{x\to 3+}{\mathop{\lim }}\,f(x)=0\]
B) \[\underset{x\to 3-}{\mathop{\lim }}\,f(x)=0\]
C) \[\underset{x\to 3+}{\mathop{\lim }}\,f(x)\ne \underset{x\to 3-}{\mathop{\lim }}\,f(x)\]
D) None of these
Correct Answer: C
Solution :
\[\underset{x\to 3+}{\mathop{\lim }}\,f(x)=5-3=2,\,\underset{x\to 3-}{\mathop{\lim }}\,f(x)=\frac{2}{5-3}=1.\]
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