A) 0
B) 1
C) \[\infty \]
D) None of these
Correct Answer: A
Solution :
\[\underset{x\to 0+}{\mathop{\lim }}\,\frac{x}{1+{{e}^{-1/x}}}=0\] as \[{{e}^{-1/x}}\to 0\] when \[x\to {{0}^{+}}\]
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