A) 0
B) 1
C) Does not exist
D) None of these
Correct Answer: C
Solution :
\[\underset{x\to 1-}{\mathop{\lim }}\,[x]=\underset{h\to 0}{\mathop{\lim }}\,\,[1-h]=\underset{h\to 0}{\mathop{\lim }}\,0=0\] and \[\underset{x\to 1+}{\mathop{\lim }}\,[x]=\underset{h\to 0}{\mathop{\lim \,\,}}\,[1+h]=\underset{h\to 0}{\mathop{\lim }}\,\,\,1=1\] Hence limit does not exist.
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