JEE Main & Advanced Mathematics Functions Question Bank Limits

  • question_answer
    \[\underset{x\to 3}{\mathop{\lim }}\,\left\{ \frac{x-3}{\sqrt{x-2}-\sqrt{4-x}} \right\}=\] [MNR 1991]

    A)                 1

    B)                 2

    C)                 ?1

    D)                 ?2

    Correct Answer: A

    Solution :

                       \[\underset{x\to 3}{\mathop{\lim }}\,\,\left\{ \frac{x-3}{\sqrt{x-2}-\sqrt{4-x}} \right\}=\underset{x\to 3}{\mathop{\lim }}\,\,\frac{(x-3)\,\left\{ \sqrt{x-2}+\sqrt{4-x} \right\}}{2\,(x-3)}=1\].                 Aliter : Apply L-Hospital?s rule.


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