JEE Main & Advanced Mathematics Functions Question Bank Limits

  • question_answer
    \[\underset{x\to \infty }{\mathop{\lim }}\,\frac{(x-1)(2x+3)}{{{x}^{2}}}=\]

    A)                 1

    B)                 ?1

    C)                 2

    D)                 None of these

    Correct Answer: C

    Solution :

                    \[\underset{x\to \infty }{\mathop{\lim }}\,\,\,\frac{(x-1)\,\,(2x+3)}{{{x}^{2}}}=\underset{x\to \infty }{\mathop{\lim }}\,\,\,\frac{2{{x}^{2}}+x-3}{{{x}^{2}}}=2.\]


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