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JEE Main & Advanced Mathematics Functions Question Bank Limits

  • question_answer
    \[\underset{x\to 0}{\mathop{\lim }}\,\frac{{{y}^{2}}}{x}=........\], where \[{{y}^{2}}=ax+b{{x}^{2}}+c{{x}^{3}}\]

    A)                 0

    B)                 1

    C)                 a

    D)                 None of these

    Correct Answer: C

    Solution :

                    \[\underset{x\to 0}{\mathop{\lim }}\,\,\frac{ax+b{{x}^{2}}+c{{x}^{3}}}{x}=\underset{x\to 0}{\mathop{\lim }}\,\,\frac{a+bx+c{{x}^{2}}}{1}=a.\]


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