A) 0
B) \[\frac{3}{7}\]
C) \[\frac{1}{2}\]
D) \[-\frac{1}{6}\]
Correct Answer: B
Solution :
\[\underset{x\to 1}{\mathop{\lim }}\,\,\frac{(x-1)\,\,({{x}^{2}}+x+1)}{(x-1)\,\,(x+6)}=\frac{3}{7}\].
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