A) \[\frac{1}{3}\]
B) \[\frac{1}{2}\]
C) \[\frac{2}{3}\]
D) \[-\frac{2}{3}\]
Correct Answer: B
Solution :
\[\underset{x\to 1}{\mathop{\lim }}\,\,\frac{1-{{x}^{-1/3}}}{(1-{{x}^{-1/3}})\,\,(1+{{x}^{-1/3}})}=\frac{1}{2}.\] Aliter : Apply L-Hospital?s rule.
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