A) 0
B) \[\frac{1}{2}\]
C) \[\frac{1}{3}\]
D) None of these
Correct Answer: A
Solution :
\[\underset{x\to 0}{\mathop{\lim }}\,\,\frac{2\,{{\sin }^{2}}(x/2)}{x}=0.\] Aliter : Apply L-Hospital?s rule.
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