JEE Main & Advanced Mathematics Functions Question Bank Limits

  • question_answer
    \[\underset{x\to \infty }{\mathop{\lim }}\,\frac{3{{x}^{2}}+2x-1}{2{{x}^{2}}-3x-3}=\]

    A)                 1

    B)                 3

    C)                 \[\frac{3}{2}\]

    D)                 \[-\frac{3}{2}\]

    Correct Answer: C

    Solution :

                    \[\underset{x\to \infty }{\mathop{\lim }}\,\,\,\frac{3+(2/x)-(1/{{x}^{2}})}{2-(3/x)-(3/{{x}^{2}})}=\frac{3}{2}.\]


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