A) 0
B) 1
C) 5/3
D) 3/5
Correct Answer: C
Solution :
\[\underset{x\to 0}{\mathop{\lim }}\,\,\frac{x\,{{[}^{5}}{{C}_{1}}{{+}^{5}}{{C}_{2}}x{{+}^{5}}{{C}_{3}}{{x}^{2}}{{+}^{5}}{{C}_{4}}{{x}^{3}}{{+}^{5}}{{C}_{5}}{{x}^{4}}]}{x\,{{[}^{3}}{{C}_{1}}{{+}^{3}}{{C}_{2}}x{{+}^{3}}{{C}_{3}}{{x}^{2}}]}\] \[=\frac{5}{3}.\] Aliter : Apply L-Hospital?s rule.You need to login to perform this action.
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