JEE Main & Advanced Mathematics Functions Question Bank Limits

  • question_answer
    \[\underset{x\to \pi /4}{\mathop{\lim }}\,\frac{\sqrt{2}\cos x-1}{\cot x-1}=\] [BIT Ranchi 1989; IIT 1990]

    A)                 \[\frac{1}{\sqrt{2}}\]

    B)                 \[\frac{1}{2}\]

    C)                 \[\frac{1}{2\sqrt{2}}\]

    D)                 1

    Correct Answer: B

    Solution :

                       \[\underset{x\to \pi /4}{\mathop{\lim }}\,\,\frac{(\sqrt{2}-\sec x)\,\cos x\,(1+\cot x)}{\cot x\,[2-{{\sec }^{2}}x]}\]                    \[=\underset{x\to \pi /4}{\mathop{\lim }}\,\frac{\sin x\,(1+\cot x)}{(\sqrt{2}+\sec x)}=\frac{\frac{1}{\sqrt{2}}(2)}{\sqrt{2}+\sqrt{2}}=\frac{1}{2}.\]                                 Aliter : Apply L-Hospital?s rule.


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