A) 0
B) \[\frac{1}{2}\]
C) 1
D) \[\infty \]
Correct Answer: B
Solution :
Let \[{{\tan }^{-1}}2x=\theta \,\Rightarrow x=\frac{1}{2}\tan \theta \] and as \[x\to 0,\,\,\theta \to 0\] \[\Rightarrow \,\,\underset{x\to 0}{\mathop{\lim }}\,\,\frac{x}{{{\tan }^{-1}}2x}=\underset{\theta \to 0}{\mathop{\lim }}\,\,\frac{\frac{1}{2}\tan \theta }{\theta }=\frac{1}{2}\].
You need to login to perform this action.
You will be redirected in
3 sec
