A) \[\frac{1}{3}\]
B) 3
C) 4
D) \[\frac{1}{4}\]
Correct Answer: C
Solution :
\[\underset{x\to 0}{\mathop{\lim }}\,\,3.\frac{\sin \,3x}{3x}+\underset{x\to 0}{\mathop{\lim }}\,\,\frac{\sin \,x}{x}=3+1=4.\]
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