JEE Main & Advanced Mathematics Functions Question Bank Limits

  • question_answer
    \[\underset{x\to \pi /2}{\mathop{\lim }}\,\frac{1+\cos 2x}{{{(\pi -2x)}^{2}}}=\] [DSSE 1986; AI CBSE 1986]

    A)                 \[1\]

    B)                 \[2\]

    C)                 3

    D)                 \[\frac{1}{2}\]

    Correct Answer: D

    Solution :

                       \[\pi -2x=\theta \,\,\Rightarrow \,\,x=\frac{\pi }{2}-\frac{\theta }{2}\] and as \[x\to \,(\pi /2),\,\,\theta \to 0\]                 Now solve yourself.


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