A) \[\frac{n}{m}\]
B) \[\frac{m}{n}\]
C) \[mn\]
D) None of these
Correct Answer: B
Solution :
\[\Rightarrow \,\,\underset{x\to 0}{\mathop{\lim }}\,\,\frac{x\,\left\{ 1+a\,\left( 1-\frac{{{x}^{2}}}{2\,\,!}+\frac{{{x}^{4}}}{4\,\,!}-\frac{{{x}^{6}}}{6\,\,!}+... \right) \right\}-b\,\left\{ x-\frac{{{x}^{3}}}{3\,\,!}+\frac{{{x}^{5}}}{5\,\,!}-... \right\}}{{{x}^{3}}}=1\] (formula).
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