A) 0
B) \[\frac{1}{3}\]
C) 3
D) \[\frac{1}{2}\]
Correct Answer: A
Solution :
\[\underset{x\to 0}{\mathop{\lim }}\,\,\,\frac{{{x}^{2}}}{\sin {{x}^{2}}}.\underset{x\to 0}{\mathop{\lim }}\,\,x\,=0.\]
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