A) \[11x-y-3z=35\]
B) \[11x+y-3z=35\]
C) \[11x-y+3z=35\]
D) None of these
Correct Answer: D
Solution :
\[a\,(x-4)+b\,(y-3)+c\,(z-2)=0\] \[\therefore \,\,\,a+b+2c=0\] and \[a-4b+5c=0\] \[\frac{a}{5+8}=\frac{b}{2-5}=\frac{c}{-4-1}=k\] \[\frac{a}{13}=\frac{b}{-3}=\frac{c}{-5}=k\] Therefore, the required equation of plane is \[-13x+3y+5z+33=0\].You need to login to perform this action.
You will be redirected in
3 sec