A) \[6x+3y+2z=0\]
B) \[x+2y+3z=0\]
C) \[3x+2y+z=0\]
D) None of these
Correct Answer: A
Solution :
Obviously the line is \[\frac{x}{6}=\frac{y}{3}=\frac{z}{2}.\] So required plane is \[6\,(x-0)+3\,(y-0)+2\,(z-0)=0\].You need to login to perform this action.
You will be redirected in
3 sec