A) \[4x-y-2z+6=0\]
B) \[4x-y+2z+6=0\]
C) \[4x-y-2z-6=0\]
D) None of these
Correct Answer: D
Solution :
Equation of plane passing through the point (1,0,?1) is, \[a(x-1)+b(y-0)+c(z+1)=0\] ??(i) Also, plane (i) is passing through (3, 2, 2) \[\therefore \] \[a\,(3-1)+b\,(2-0)+c\,(2+1)=0\] or \[2a+2b+3c=0\] ?..(i) Plane (i) is also parallel to the line\[\frac{x-1}{2}=\frac{y-1}{-2}=\frac{z-2}{3}\] \[\therefore \]\[2a-2b+3c=0\] ?..(ii) From (i) and (ii),\[\,\,\frac{a}{-3}=\frac{b}{0}=\frac{c}{2}\] Therefore, the required plane is, \[-3\,(x-1)+0\,(y-0)\,+2\,(z+1)=0\] or \[-\,3x+2z+5=0\].You need to login to perform this action.
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