A) \[8x+14y+13z+37=0\]
B) \[8x-14y+13z+37=0\]
C) \[8x+14y-13z+37=0\]
D) \[8x+14y+13z-37=0\]
E) (e) \[8x-14y-13z-37=0\]
Correct Answer: A
Solution :
Equation of plane passing through the point (2, ?1, ?3) is, Also, \[A(x-2)+B(y+1)+C(z+3)=0\] Also, \[3A+2B-4C=0\] and \[2A-3B+2C=0\] \ \[\frac{A}{-8}=\frac{B}{-14}=\frac{C}{-13}=k\], (Let) So, \[A=-8k,B=-14k,C=-13k\] Equation of required plane is, \[-k[8(x-2)+14(y+1)+13(z+3)]=0\] i.e., \[8x+14y+13z+37=0\].You need to login to perform this action.
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