A) (0, 1, ?2)
B) (1, 2, 3)
C) (?1, 9, ?25)
D) \[\left( \frac{-1}{11},\frac{9}{11}\frac{-25}{11} \right)\]
Correct Answer: D
Solution :
\[\frac{x}{1}=\frac{y-1}{2}=\frac{z+2}{3}=r\], (say) So, \[x=r\], \[y=2r+1\], \[z=3r-2\] \[\therefore \,\,\,2r+3\,(2r+1)+(3r-2)=0\,\,\Rightarrow r=\frac{-1}{11}\] Hence, \[x=\frac{-1}{11},\,y=\frac{9}{11},\,\,z=-\frac{25}{11}\].You need to login to perform this action.
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