A) \[\frac{x-a}{a-b}=\frac{y-b}{b-c}=\frac{z-c}{c-a}\]
B) \[\frac{x-a}{b}=\frac{y-b}{c}=\frac{z-c}{a}\]
C) \[\frac{x-a}{a}=\frac{y-b}{b}=\frac{z-c}{c}\]
D) \[\frac{x-a}{2a-b}=\frac{y-b}{2b-c}=\frac{z-c}{2c-a}\]
Correct Answer: B
Solution :
Required line is , \[\frac{x-a}{a-b-a}=\frac{y-b}{b-c-b}=\frac{z-c}{c-a-c}\] i.e., \[\,\,\frac{x-a}{b}=\frac{y-b}{c}=\frac{z-c}{a}\].
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