A) \[\frac{x+3}{1}=\frac{y+2}{3}=\frac{z+4}{-2}\]
B) \[\frac{x-3}{1}=\frac{y-2}{3}=\frac{z-4}{-2}\]
C) \[\frac{x+3}{7}=\frac{y+2}{7}=\frac{z+4}{6}\]
D) \[\frac{x-3}{7}=\frac{y-2}{7}=\frac{z-4}{6}\]
Correct Answer: B
Solution :
Required line is \[\frac{x-3}{4-3}=\frac{y-2}{5-2}=\frac{z-4}{2-4}\] i.e., \[\frac{x-3}{1}=\frac{y-2}{3}=\frac{z-4}{-2}\].
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