JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Line

  • question_answer
    The angle between the lines \[\frac{x+4}{1}=\frac{y-3}{2}=\frac{z+2}{3}\] and \[\frac{x}{3}=\frac{y-1}{-2}=\frac{z}{1}\] is

    A)                                                               \[{{\sin }^{-1}}\left( \frac{1}{7} \right)\]

    B)                                                               \[{{\cos }^{-1}}\left( \frac{2}{7} \right)\]

    C)                                                               \[{{\cos }^{-1}}\left( \frac{1}{7} \right)\]

    D)                                                               None of these

    Correct Answer: C

    Solution :

                     Angle between two lines,                                    \[\cos \theta =\frac{{{a}_{1}}{{a}_{2}}+{{b}_{1}}{{b}_{2}}+{{c}_{1}}{{c}_{2}}}{\sqrt{a_{1}^{2}+b_{1}^{2}+c_{1}^{2}}\sqrt{a_{2}^{2}+b_{2}^{2}+c_{2}^{2}}}\]       \[\therefore \,\,\,\cos \theta =\frac{1\times 3+2\times -2+3\times 1}{\sqrt{{{1}^{2}}+{{2}^{2}}+{{3}^{2}}}\sqrt{{{3}^{2}}+{{(-2)}^{2}}+{{1}^{2}}}}\]\[=\frac{2}{\sqrt{14}\sqrt{14}}\]                                                               \[\therefore \,\,\theta ={{\cos }^{-1}}\left( \frac{1}{7} \right)\].


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