A) \[{{\cos }^{-1}}(1/65)\]
B) \[{{\cos }^{-1}}(2/65)\]
C) \[{{\cos }^{-1}}(3/65)\]
D) \[\pi /2\]
Correct Answer: A
Solution :
\[\theta ={{\cos }^{-1}}\frac{(-15-48+65)}{\sqrt{25+144+169}\sqrt{9+16+25}}\] = \[{{\cos }^{-1}}\left( \frac{2}{(13\sqrt{2})\,(5\sqrt{2})} \right)\] = \[{{\cos }^{-1}}\left( \frac{1}{65} \right)\].
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