JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Line

  • question_answer
    The angle between the lines \[\frac{x}{1}=\frac{y}{0}=\frac{z}{-1}\] and \[\frac{x}{3}=\frac{y}{4}=\frac{z}{5}\] is [Pb. CET 2002]

    A)                                                               \[{{\cos }^{-1}}\frac{1}{5}\]

    B)                                                               \[{{\cos }^{-1}}\frac{1}{3}\]

    C)                                                               \[{{\cos }^{-1}}\frac{1}{2}\]

    D)                                                               \[{{\cos }^{-1}}\frac{1}{4}\]

    Correct Answer: A

    Solution :

                     \[\theta ={{\cos }^{-1}}\,\left( \frac{3+0-5}{\sqrt{1+1}\sqrt{9+16+25}} \right)\]                                                                          \[={{\cos }^{-1}}\,\left( \frac{-2}{\pm 10} \right)={{\cos }^{-1}}\left( \frac{1}{5} \right)\].


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