A) \[\sqrt{30}\]
B) \[2\sqrt{30}\]
C) \[5\sqrt{30}\]
D) \[3\sqrt{30}\]
Correct Answer: D
Solution :
S.D.\[=\]\[\frac{\left| \begin{matrix} 6 & 15 & -3 \\ 3 & -1 & 1 \\ -3 & 2 & 4 \\ \end{matrix} \right|}{\sqrt{{{(-4-2)}^{2}}+{{(12+3)}^{2}}+{{(6-3)}^{2}}}}\] \[=\,\,\frac{270}{\sqrt{270}}=\sqrt{270}\] = \[3\sqrt{30}\].You need to login to perform this action.
You will be redirected in
3 sec