JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Line

  • question_answer
    The distance of the point (2, 3, 4) from the line \[1-x=\frac{y}{2}=\frac{1}{3}(1+z)\] is [J & K 2005]

    A)                                                               \[\frac{1}{7}\sqrt{35}\]

    B)                                                               \[\frac{4}{7}\sqrt{35}\]

    C)                                                               \[\frac{2}{7}\sqrt{35}\]

    D)                                                               \[\frac{3}{7}\sqrt{35}\]

    Correct Answer: D

    Solution :

                    Required distance = \[\sqrt{\sum {{({{x}_{1}}-{{x}_{2}})}^{2}}-{{[\sum l({{x}_{1}}-{{x}_{2}})]}^{2}}}\]                                   \[=\frac{3}{7}\sqrt{35}\].


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