JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Line

  • question_answer
    The angle between the lines whose direction cosines are proportional to (1, 2, 1) and (2, ?3, 6) is

    A)                                                               \[{{\cos }^{-1}}\left( \frac{2}{7\sqrt{6}} \right)\]

    B)                                                               \[{{\cos }^{-1}}\left( \frac{1}{7\sqrt{6}} \right)\]

    C)                                                               \[{{\cos }^{-1}}\left( \frac{3}{7\sqrt{6}} \right)\]

    D)                                                               \[{{\cos }^{-1}}\left( \frac{5}{7\sqrt{6}} \right)\]

    Correct Answer: A

    Solution :

                     \[\theta ={{\cos }^{-1}}\left[ \frac{(1)(2)+(2)(-3)+(1)(6)}{\sqrt{{{1}^{2}}+{{2}^{2}}+{{1}^{2}}}\sqrt{{{2}^{2}}+{{(-3)}^{2}}+{{6}^{2}}}} \right]\]                                                                       \[{{\cos }^{-1}}\,\left[ \frac{2-6+6}{\sqrt{6}\sqrt{49}} \right]={{\cos }^{-1}}\left[ \frac{2}{7\sqrt{6}} \right]\].


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