A) \[{{e}^{\sin x}}\]
B) \[\frac{1}{\sin x}\]
C) \[\frac{1}{\cos x}\]
D) \[{{e}^{\cos x}}\]
Correct Answer: C
Solution :
\[\frac{dy}{dx}+y\tan x=\sec x\], where \[p=\tan x,\ \ Q=\sec x\] This is the linear differential equation in y, hence I.F. \[={{e}^{\int_{{}}^{{}}{pdx}}}={{e}^{\int_{{}}^{{}}{\tan x\,dx}}}\]; I.F. \[={{e}^{\log \sec x}}=\sec x\].You need to login to perform this action.
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