A) -4
B) 4
C) 3
D) -2
Correct Answer: B
Solution :
(b): \[\frac{3}{x-1}+\frac{1}{x-3}=\frac{4}{x-2}\] \[\Rightarrow \frac{3}{x-1}+\frac{1}{x-3}=\frac{3}{x-2}+\frac{1}{x-2}\] \[\Rightarrow \frac{3}{x-1}-\frac{3}{x-2}=\frac{1}{x-2}-\frac{1}{x-3}\] \[\Rightarrow \frac{3x-6-3x+3}{x-1}=\frac{x-3-x+2}{x-2}\] \[\Rightarrow \frac{-3}{x-1}=\frac{-1}{x-3}\] \[\Rightarrow \frac{-3}{x-1}=\frac{1}{x-3}\] \[\Rightarrow 3x-9=x-1\Rightarrow 2x=8\Rightarrow x=4\]You need to login to perform this action.
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