A) \[b-a+c\]
B) \[0\]
C) \[a-b-c\]
D) \[a+b+c\]
Correct Answer: B
Solution :
(b): Simply by adding three eqns. \[2(x+y+z)=0\Rightarrow \frac{x+y+z}{3}\] = Average = 0You need to login to perform this action.
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