A) 1/2
B) -3/2
C) 3/2
D) 1
Correct Answer: B
Solution :
(b): \[\frac{3x+4}{x+1}=\frac{3x+2}{x-1},x\ne 1\] \[x\ne 1\]is written in order to make the question complete, as if x =1 then \[\frac{3x+2}{x-1}=\frac{3x+2}{0}\]=undefined Now solving \[\left( 3x+4 \right)\left( x-1 \right)=\left( 3x+2 \right)\left( x+1 \right)\] \[\Rightarrow \cancel{3{{x}^{2}}}+x-4=\cancel{3{{x}^{2}}}+5x+2\] \[\Rightarrow -6=4x\] \[\Rightarrow x=\frac{-3}{2}\]You need to login to perform this action.
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