A) \[12\]
B) \[6\]
C) \[2\]
D) \[4\]
Correct Answer: A
Solution :
Given \[3a+2b+c=22\] \[b+c=8\]and \[c=6\] Therefore, \[~b=8-c=8-6=2\] and a \[a=\frac{22-c-2b}{3}\] \[=\frac{22-10}{3}=\frac{12}{3}=4\] Hence \[a+b+c=4+2+6=12\] \[=Rs.\,\,5306.04\]You need to login to perform this action.
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