A) 4 units
B) 3 units
C) 5 units
D) None of these
Correct Answer: C
Solution :
Put \[x=0\]in \[4x+3y=12,\]we get \[4\times 0+3y=12\Rightarrow y=4.\] Put y = 0 in \[4x+3y=12,\]we get \[4x+3\times 0=12\,\,\Rightarrow x=3.\] So, OB = 4 units and OA = 3 units. Now, in \[\Delta \Alpha {\mathrm O}\Beta ,\]by Pythagoras theorem \[A{{B}^{2}}=O{{B}^{2}}+O{{A}^{2}}\Rightarrow A{{B}^{2}}={{4}^{2}}+{{3}^{2}}\] \[\Rightarrow \]\[A{{B}^{2}}=16+9\Rightarrow AB=\sqrt{25}=5\] Hence, hypotenuse = 5 units.You need to login to perform this action.
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