A) \[{{160}^{{}^\circ }}\]
B) \[{{120}^{{}^\circ }}\]
C) \[{{180}^{{}^\circ }}\]
D) \[{{210}^{{}^\circ }}\]
Correct Answer: C
Solution :
(c): \[a+x={{180}^{{}^\circ }}\] \[c+x=b\Rightarrow x=b-c\] \[\therefore \]\[a+\left( b-c \right)={{180}^{{}^\circ }}\] \[\Rightarrow \]\[a+b-c={{180}^{{}^\circ }}\]You need to login to perform this action.
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