A) \[{{50}^{{}^\circ }}\]
B) \[{{60}^{{}^\circ }}\]
C) \[{{80}^{{}^\circ }}\]
D) \[{{55}^{{}^\circ }}\]
Correct Answer: C
Solution :
(c): Let \[\angle AEB={{x}^{{}^\circ }}\]. Now, \[AB\parallel CD\] and BC is the transversal. \[\therefore \]\[\angle ABE=\angle BCD={{55}^{{}^\circ }}\] In \[\Delta ABE\] we have \[{{45}^{{}^\circ }}+{{55}^{{}^\circ }}+x={{180}^{{}^\circ }}\] \[\Rightarrow \]\[x={{80}^{{}^\circ }}.\]You need to login to perform this action.
You will be redirected in
3 sec