A) \[{{48}^{o}}\]
B) \[{{90}^{o}}\]
C) \[{{42}^{o}}\]
D) \[{{110}^{o}}\]
Correct Answer: A
Solution :
Clearly \[p={{360}^{o}}-{{270}^{o}}={{90}^{o}}\] (Angles at a point) Through C, draw a line Z parallel to AB and DE. \[\therefore \] \[{{42}^{o}}+x={{180}^{o}}\] and \[q+y={{180}^{o}}\] \[\Rightarrow \] \[x={{180}^{o}}-{{42}^{o}}={{138}^{o}}\] \[\therefore \] \[y={{270}^{o}}-{{138}^{o}}={{132}^{o}}\] \[\therefore \] \[q={{180}^{o}}-{{132}^{o}}={{48}^{o}}\]You need to login to perform this action.
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