A) \[\angle AOQ<\angle BOP\]
B) \[\angle AOQ>\angle BOP\]
C) \[\angle AOP={{180}^{{}^\circ }}-\angle AOQ\]
D) \[\angle AOP={{90}^{{}^\circ }}-\angle AOQ\]
Correct Answer: C
Solution :
(c): Here, as given \[\angle AOP=\angle BOQ\] POQ is a straight line. So \[\angle AOP+\angle AOQ={{180}^{{}^\circ }}\] \[\angle AOP={{180}^{{}^\circ }}-\angle AOQ\]You need to login to perform this action.
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